Q9 1 Point Curl Vf = 0 for every differentiable function f. Enter your answer here Q10 1 Point What is the correct geometric interpretation of f, (4, 5)? O The normal vector to the plane tangent to the surface z = f (r, y) at the point (4, 5) O The slope of the line tangent to the surface z = f (r, y) at the point (4, 5) O The slope of the line tangent to the surface z = f (r. y) at the point (4, 5) along the line O The slope of jim of the line tangent to the surface = = f(x, y) at the point (4, 5) along the line y = Q11 Point for (4, 5) - 5. fyy(4, 5) = 2, and fry ( 4, 5) = -4. Then A