Qm sin Consider the LC circuit shown below. 1. 1 = VLC VLC Switch S is initially open, and the capaci- tor has a charge Qm on its plates. At t = 0 Qm 2. I = COS the switch is closed. VLC VLC C L 0080 3. I = - m C cos VLC Qm S 4. I = Q m VLC Qm What will be the current through the in- 5. 1 = sin2 VLC ductor as a function of time? 0 6. 1 =- Qm cos2 C 2m sin 0 7 . 1 = C O 8. I = Qm exp VLC VLC 9. 1 = Qm sin2