QUESTION 13

 How many moles of Mg P2(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 m P.(s)? \n

1. How many moles of Mg₃P₂(s) can be produced from the reaction of 0.14 mol Mg(s) with 0.020 mol P₄(s)?
           6 Mg(s) + P₄(s) → 2 Mg₃P₂(s)

   		0.14 mol
   		0.047 mol
   		0.42 mol
   		0.040 mol
   		0.020 mol

Answer rating: 100% (QA)

Ans The balanced chemical equation of the reaction is as follows 6Mg s P4s 2Mg3P2 s We ... View the full answer