Question: Question 2 a ) Given a triangular 1 - hr UH with TB = 1 2 h r ( time base of the UH )

Question 2
a) Given a triangular 1-hr UH with
TB =12hr(time base of the UH)
TR=4hr(time of rise)
QP=200cfs(peak flow)
Develop a storm hydrograph for hourly rainfall (in) of P=[0.1,0.5,1.2].
b) Repeat the above problem for hourly rainfall (in) of P=[0.2,1.0,2.4].
Hint
In Question 2, use the given parameters to plot the triangular hydrograph.
Use the triangular hydrograph to get ordinates (UH)
Use the given Pn values and the UH ordinates from above in Convolution method to get the Q values.
Repeat the same process with the other set of given Pn and calculate the new Q values * Compare the 2Q values.
3 values are given, Qp is your peak flow value that happens at TR. TB is when flow value is zero again. Basically, you will need to create a triangular graph like Question 1, with (0,0),(TR, QP) and (TB,0). Once you have the graph, you can follow the steps you did in Question 1 and extract your UH values from the graph, multiply Pn by UH and lag as needed and get your total Q values. Keep in mind that in Part b, you have a new set of Pn values but the UH values stays the same as Part a. Repeat the Pn (new values) multiplied by UH, lag and calculate the Q.
For both questionfy, once you have the final Q values, plot it against time to have a hydrograph.
Question 2 a ) Given a triangular 1 - hr UH with

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