Question $3(1$ point$)$

Use logarithmic differentiation $to$ find the derivative $of$ the function.

$y=\sqrt[6]{\frac{x^2+1}{x^2-1}}$

$y^{\text{'}}=-\frac{6x}{x^4-1}\sqrt[6]{\frac{x^2+1}{x^2-1}}$

$y^{\text{'}}=-\frac{4x}{6(x^4-1)}\sqrt[6]{\frac{x^2+1}{x^2-1}}$

$y^{\text{'}}=\frac{24x}{x^4-1}\sqrt[6]{\frac{x^2+1}{x^2-1}}$

$y^{\text{'}}=-\frac{24x}{x^4-1}$