Question 7 (Mandatory) (6 points) Toss 2 dice, and let the event be the sum of the values of the top faces. The possible outcomes are computed inside the following table at the intersection of the row of the "toss of 1st die" and the column of "toss of 2nd die": loss of 2nd die 1st dic Because there are 36 outcomes, the probability of a sum = frequency of the sum/36. So, the probabilities of the sums are Sum Probability 1/36 2/36 4 3/36 5 4/36 6 5/36 7 6/36 8 5/36 9 4/36 10 3/36 11 2/36 12 1/36 Only one of the sums 2 through 12 can occur in a single toss of the dice. These are mutually exclusive events. The Simple Addition Rule P(A or B) = P(A) + P(B applies). Additional Reading Match the items on the left to the items on the right. 0.000 1. P(X at least 7) 0.583 2. P(X is not 9) 0.889 3. P(X = 1)