Question: Reaction 1 NH 4 Cl ( s ) - > NH 4 Cl ( aq ) Delta H = 1 7 . 3 3 KJ

Reaction 1 NH4Cl (s)-> NH4Cl(aq) Delta H=17.33KJ
Reaction 2 NH3(aq)+ HCl (aq)-> NH4Cl (aq )Delta H=-78.835KJ
Reaction 31/2 N2(g)+3/2 H2(g)-> NH3(g)\Delta Ho =-45.9 kJ
Reaction 4 NH3(g)-> NH3(aq)\Delta Ho =-30.5 kJ
Reaction 51/2 H2(g)+1/2 Cl2(g)-> HCl (g)\Delta Ho =-92.3kJ
Reaction 6 HCl (g)-> HCl(aq)\Delta Ho =-74.8 kJ
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Reaction 71/2 N2(g)+2 H2(g)+1/2 Cl2(g)-> NH4Cl (s) Delta H =?
Can some one help me determine the delta H of the 7 equation by using Hess's Law? but the question asks me to manipulate 6 equations above too

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