Recall that in Module 4, we learned the expected value for a discrete random variable X...

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Recall that in Module 4, we learned the expected value for a discrete random variable X is defined as ΣXP(X=x), and the variance for a discrete random variable is defined as Σ(x - E(X))²P(X=x). Suppose that we have a discrete random variable with only two possible values 1 and 0, which occur with probability p and 1-p, so that P(X=1) =p, and P(X=0) = 1-p. What is the expected value of this discrete random variable X? What is the variance of this discrete random variable X? (Select all that apply) The Variance of X is p(1-p) The expected value of X is p The expected value of X is calculated by 1*p+0*(1-p) - The variance of X can be calculated by (1 − p)²*p + (0-p)² + (1 - p) Recall that in Module 4, we learned the expected value for a discrete random variable X is defined as ΣXP(X=x), and the variance for a discrete random variable is defined as Σ(x - E(X))²P(X=x). Suppose that we have a discrete random variable with only two possible values 1 and 0, which occur with probability p and 1-p, so that P(X=1) =p, and P(X=0) = 1-p. What is the expected value of this discrete random variable X? What is the variance of this discrete random variable X? (Select all that apply) The Variance of X is p(1-p) The expected value of X is p The expected value of X is calculated by 1*p+0*(1-p) - The variance of X can be calculated by (1 − p)²*p + (0-p)² + (1 - p)

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For a discrete random variable X having the possible values x ... View the full answer