Recall that there are $5$ basic relational algebra operators: $,,,-,$

Assume T$1,$ T$2$ and T$3$ are relations:

T$1$ has schema $\{x\}$

T$2$ has schema $\{x,y\}$

T$3$ has schema $\{x,y,z\}$

Rewrite the following relational algebra queries using only the $5$ basic operators $($plus

the renaming operator if desired$).$ This is the only part of the assignment where we

don't want you to use the complex operators such as natural join.

$T2|><mi\; id="EditorElement\_2155943">|</mi><mi\; id="EditorElement\_2155945">T</mi><mn\; id="EditorElement\_2155947">3</mn>$

${}_x(T2)T1$

$T\frac{2}{T}1$