Refer to the table from the previous problem (provided below) to answer the question. West East North Total Non-Defective 96 1073 1204 2373 Defective 13 50 64 127 Total 109 1123 1268 2500 Calculate the test statistic and provide the corresponding P-value for this table. Then use the a = 0.05 significance level and your answer to form a conclusion regarding the null hypothesis. O A. x2 = 11.52, P-value = 0.012. Therefore the null hypothesis is rejected, (P-value is less than 0.05). O B. x2 = 11.52, P-value = 0.012. Therefore the null hypothesis is not rejected, (P-value is less than 0.05). O C. x2 = 11.52, P-value = 0.0032. Therefore the null hypothesis is not rejected, (P-value is greater than 0.05). O D. x2 = 11.52, P-value = 0.0032. Therefore the null hypothesis is rejected, (P-value is less than 0.05)