Section: 08 METHOD 1: TITRATION WITH BURET AND INDICATOR. Trial 1 Trial 2 Trial 3 Initial...

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Section: 08 METHOD 1: TITRATION WITH BURET AND INDICATOR. Trial 1 Trial 2 Trial 3 Initial buret reading 0.21 mL 1.95mL 2.75mL Final buret reading 33.35ml 25.65mL 26.55 mL NaOH (aq) Volume 23.14 mL 23.7 mL 23.8mL 0.09978 mol NaOH. IL NAOH X Calculated moles of NaOH (aq) base used to titrate the acid in 5.00 mL aliquot of acid: 0.002309 mol (show your calculations) NaOH 0.02314 NaOH Calculated M (mols/L) of the unknown HCl(aq) Trial 1 (Show a sample calculation for one trial) 0.002309 mol NaOH Trial 2 Score: /20 Imol HCl 0.09978 M NaOH (from the container) Average concentration of unknown acid concentration (M) = 0.002309 mol NaOH Trial 3 0.002309 mol HCI 0.00 500L -3 =1.066X10M HC1 Section: 08 METHOD 1: TITRATION WITH BURET AND INDICATOR. Trial 1 Trial 2 Trial 3 Initial buret reading 0.21 mL 1.95mL 2.75mL Final buret reading 33.35ml 25.65mL 26.55 mL NaOH (aq) Volume 23.14 mL 23.7 mL 23.8mL 0.09978 mol NaOH. IL NAOH X Calculated moles of NaOH (aq) base used to titrate the acid in 5.00 mL aliquot of acid: 0.002309 mol (show your calculations) NaOH 0.02314 NaOH Calculated M (mols/L) of the unknown HCl(aq) Trial 1 (Show a sample calculation for one trial) 0.002309 mol NaOH Trial 2 Score: /20 Imol HCl 0.09978 M NaOH (from the container) Average concentration of unknown acid concentration (M) = 0.002309 mol NaOH Trial 3 0.002309 mol HCI 0.00 500L -3 =1.066X10M HC1

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Trial 1 Initial buret reading 021 mL Final buret reading 3335 mL NaOH aq volume 3314 mL 009978 M NaO... View the full answer