Question: select l . name, min ( o . amount ) as min _ offer, round ( avg ( o . amount ) , 2 )

select l.name, min(o.amount) as min_offer, round(avg(o.amount),2)as avg_offer,
max(o.amount) as max_offer, count(amount)as offers from lots l inner join offers o ON
l.id=o.lot_id
ORDER by name
group by offers;

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