Question: Show that | 3a -a+b -a+c, -b+a 3b -b+c, -c+a -c+b 3c|= 3(a+b+c)(ab+bc+ca).

Show that | 3a -a+b -a+c, -b+a 3b -b+c, -c+a -c+b 3c|=

Show that | 3a -a+b -a+c, -b+a 3b -b+c, -c+a -c+b 3c|= 3(a+b+c)(ab+bc+ca).

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