Sir, i am stuck on this question only need an answer no need of an explanation

For the power series OO n=1 bn+1 you are given that lim n-+00 on Hence, the open inteval of convergence for the above power series is (A, B) where A = Number and B= Number Now, the open interval of convergence for the power series bn n An n= 1 is (C, D) where C = Number and D = Number and for n=1 it is (M, N) where M = Number and N = Number(3 mark) Consider the function F : IR2 -> IR given by F(x, z) = 327 . f(x) . where f : R -> R is a differentiable function. i) Evaluate the partial derivative Fz = ( express in terms of x, z and/or f(I) ) ii) It is given that F satisfies the partial differential equation zFr = CFz with the condition F(1, 2) = 16 Using the shorthand notation y = f(), the above partial diferential equation becomes an ODE ury (express in terms of r and/or y only) with initial condition y(1) = f(1) = Now the solution to the above ordinary differential equation(IVP) is y = f(x) = (express in terms of I only)