Solve $3x{y}^{\text{'}}-3y=x^{-7},y(1)=4.$

$($a$)$ Identify the integrating factor, $(x).$

$(x)=$

$($b$)$ Find the general solution.

$y(x)=$

$$

Note: Use C for the arbitrary constant.

$($c$)$ Solve the initial value problem $y(1)=4.$

$y(x)=$

$$