An electron (q = -1.6022 * 10-19C and m = 9.1094 10-31 kg) is accelerated from...
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An electron (q = -1.6022 * 10-19C and m = 9.1094 10-31 kg) is accelerated from rest through a potential difference AV = -10V. It then enters a magnetic field with a magnitude B = 10T with its velocity vector perpendicular to the magnetic field vector (0 = 90°). a) Using energy conservation, find the velocity (in m/s) of the electron after its been accelerated by the potential difference AV. b) Using Newton's 2nd Law find the radius (in um) of the circular path the electron follows. Use the magnitude of the charge • Remember that a = v/, for circular motion c) If a positron (q = 1.6022 * 10-19C and m = 9.1094 + 10-31kg) enters the magnetic field at the same velocity as the electron, will the radius of its circular path be the same? d) Will the positron travel in the same direction (i.e. clockwise or counterclockwise) as the electron? If not, explain why? An electron (q = -1.6022 * 10-19C and m = 9.1094 10-31 kg) is accelerated from rest through a potential difference AV = -10V. It then enters a magnetic field with a magnitude B = 10T with its velocity vector perpendicular to the magnetic field vector (0 = 90°). a) Using energy conservation, find the velocity (in m/s) of the electron after its been accelerated by the potential difference AV. b) Using Newton's 2nd Law find the radius (in um) of the circular path the electron follows. Use the magnitude of the charge • Remember that a = v/, for circular motion c) If a positron (q = 1.6022 * 10-19C and m = 9.1094 + 10-31kg) enters the magnetic field at the same velocity as the electron, will the radius of its circular path be the same? d) Will the positron travel in the same direction (i.e. clockwise or counterclockwise) as the electron? If not, explain why?
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Physics for Scientists and Engineers A Strategic Approach with Modern Physics
ISBN: 978-0133942651
4th edition
Authors: Randall D. Knight
Posted Date:
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