Question: solve for t 1 2 0 0 = 1 0 ( 2 t + 2 ) ^ 2 - 2 0 ( 2 t +

solve for t
1200=10(2t+2)^2-20(2t+2)+500

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Solve for t on 1200 2 1022 20 22 500 solving this 1200 1200 1200 By using Quadr... View full answer

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