Solve the following using the Binary system to a decimal #$,$

for example: $2^{-4}=0\mathrm{.}0625$ or ${62\mathrm{.}5}^{-3}$

$2^{-2}=$

$2^{-1}=$

${32}^3=$

$2^5=$

Example $1100\mathrm{.}11b=12\mathrm{.}75d$

Covert the binary #: $1001\mathrm{.}01$ b to

$0\mathrm{.}250,0\mathrm{.}125,8,32,9\mathrm{.}75$

$0\mathrm{.}250,0\mathrm{.}5,8,32,9\mathrm{.}25$

$0\mathrm{.}125,0\mathrm{.}05,8,64,9\mathrm{.}125$

$0\mathrm{.}125,0\mathrm{.}05,4,127,9\mathrm{.}065$