Solve the following using the Binary system to a decimal #$,$

for example: $2-4=0\mathrm{.}0625$ or $62\mathrm{.}5-3$

$1)2-2=\_\_\_\_\_\_\_\_\_\_$

$2)2-1=\_\_\_\_\_\_\_\_\_\_$

$323=\_\_\_\_\_\_\_\_\_\_\_$

$4)25=\_\_\_\_\_\_\_\_\_\_\_$

Example $1100\mathrm{.}11$b $=12\mathrm{.}75$d

$5.$ Covert the binary #: $1001\mathrm{.}01$b to $\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$d