Question: Solve the initial value problem: ty' ty = (5+2 + 20t + 3) y-2, y(1) = 1 (t> 0) y (t ) Your answer should

Solve the initial value problem: ty' ty = (5+2 + 20t + 3) y-2, y(1) = 1 (t> 0) y (t ) Your answer should be a function of t. Hint: This is a Bernoulli equation. To solve multiply by y", then set u = 3

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