Solve the problem the graphical method presented in class. Put x$1$ on X$-$axis. Clearly mark the feasible region and direction of increase$/$decrease of Z and state what the optimal solution is $($value of x$1,$ x$2,$ Z$).$ In addition, what would be the optimal solution $($value of x$1,$ x$2,$ Z$)$ if the objective function became Min Z $=2$x$1+5$x$2?(8+2=10$ marks$)$ Min Z $=2$x$1+3$x$25$x$1+10$x$2>=90[$con$1]4$x$1+3$x$2>=48[$con$2]0\mathrm{.}5$x$1>=1\mathrm{.}5[$con$3]4$x$1+2$x$2>=24[$con$4]$ x$1,$ x$2>=0$Problem $1$

Solve the problem the graphical method presented in class. Put $x_1$ on $x-$axis. Clearly mark the feasible region

and direction of increase$/$decrease of $Z$ and state what the optimal solution is $($value of $x1,x2,Z).$ In addition, what

would be the optimal solution $($value of $x1,x2,Z)$ if the objective function became Min

marks$)$

MinZ$=21+32,$

$51+10290,[$ con $1]$

$41+3248,[$ con $2]$

$0\mathrm{.}511\mathrm{.}5,[$ con $3]$

$41+2224,[$ con $4]$

$1,20,$