Solve the problem the graphical method presented in class. Put x$1$ on X$-$axis. Clearly mark the feasible region and direction of increase$/$decrease of Z and state what the optimal solution is $($value of x$1,$ x$2,$ Z$).$ In addition, what would be the optimal solution $($value of x$1,$ x$2,$ Z$)$ if the objective function became Min Z $=2$x$1+5$x$2?(8+2=10$ marks$)$ Min Z $=2$x$1+3$x$25$x$1+10$x$2>=90[$con$1]4$x$1+3$x$2>=48[$con$2]0\mathrm{.}5$x$1>=1\mathrm{.}5[$con$3]4$x$1+2$x$2>=24[$con$4]$ x$1,$ x$2>=0$