Example 2.1.1 Consider the convolution of the two rectangular pulse signals t 5 x(t) = 2rect...

  

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Example 2.1.1 Consider the convolution of the two rectangular pulse signals t 5 x(t) = 2rect h(t) = rect 2 t-2 4 x(t) * h(t) = x(X)h(t – X)dX 1 Q1) convolution a- Redo Example 2.1.1 page 16 in the Text book by calculating the output y(t) = h(t) * x(t) instead of y(t) = x(t) * h(t) using a graphical approach (hint: swap the roles of h(t) and x(t), as explained in the lecture). b- Redo it again by calculating y(t) using the convolution integral mathematically (not graphically). Show all the steps. c- Redo the original example by replacing x(t) by x(t)=8(t). Explain the results. Example 2.1.1 Consider the convolution of the two rectangular pulse signals t 5 x(t) = 2rect h(t) = rect 2 t-2 4 x(t) * h(t) = x(X)h(t – X)dX 1 Q1) convolution a- Redo Example 2.1.1 page 16 in the Text book by calculating the output y(t) = h(t) * x(t) instead of y(t) = x(t) * h(t) using a graphical approach (hint: swap the roles of h(t) and x(t), as explained in the lecture). b- Redo it again by calculating y(t) using the convolution integral mathematically (not graphically). Show all the steps. c- Redo the original example by replacing x(t) by x(t)=8(t). Explain the results.

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