Starting from $x=0$ with an initial velocity $v_0=5\frac{m}{s},$ a $10-$ kg particle is moving along a

horizontal straight line in liquid under the action of a drag resistance force: $F=\frac{20v^2}{3+x},$ where

$F,x,$ and v are expressed in $N,m,$ and $\frac{m}{s},$ respectively.

Determine velocity as a function of position: $v(x)$

Evaluate at $x=8\mathrm{.}53m$