Question: sum vec ( tau ) = ( d ( vec ( L ) ) ) / ( dt ) yields Delta L

\sum vec(\tau )=(d(vec(L)))/(dt) yields \Delta L_(z)=\int_(t_(2))^(t_(1))(\sum \tau _(z))dt=(\sum \tau _(z))_(av)\Delta t. The quantity
\int_(t_(2))^(t_(1))(\sum \tau _(z))dt is called the angular impulse.\omega _(door )=
ra(d)/(s)
\ sum vec ( \ tau ) = ( d ( vec ( L ) ) ) / ( dt

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