Question: Suppose f is a one-to-one differentiable function and its inverse function f^-1 is also differentiable. Use implicit differentiation to show that (f^-1)'(x) = (1) /
Suppose f is a one-to-one differentiable function and its inverse function f^-1 is also differentiable. Use implicit differentiation to show that
(f^-1)'(x) = (1) / (f'(f^-1(x)))
provided that the denominator is not 0.
(b)Find (f^-1)'(4) If f(-5) = 4 and f '(5) = 3/5
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