Question: Suppose that a function ff is defined recursively as f(0)=1f(0)=1, and f(n)=f(n1)+1f(n)=f(n1)+1 for all n>0n>0. What is the closed form of this function
Suppose that a function ff is defined recursively as f(0)=1f(0)=1, and f(n)=f(n1)+1f(n)=f(n1)+1 for all n>0n>0. What is the closed form of this function
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