Suppose that you are told that the Fourier coefficients of a periodic function f(t) are given...

 

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Suppose that you are told that the Fourier coefficients of a periodic function f(t) are given by F(n) == 1 4 (-1)"+1-1 2 2 n =0 otherwise (a) Use the Fourier series expansion formula (the Fourier sum) to plot the function f(t) over two periods, given that the period is T= 1 seconds. That means: use the Fourier series sum with the given coefficients and fundamental frequency. Cut off your Fourier expansion sum at some 'reasonable' number (n = 25 should work well for this problem) so that Maple can actually compute the finite sum. Plot the function (your cut-off Fourier series sum) for t=0..2 (2) since the given period is 1/2. (b) Repeat part (a) but now using a period of T=2 seconds (this means you use the same cut-off Fourier series sum, the same Fourier coefficients as part (a) but now your fundamental frequency is different). (c) What is the difference between part (a) and (b) Suppose that you are told that the Fourier coefficients of a periodic function f(t) are given by F(n) == 1 4 (-1)"+1-1 2 2 n =0 otherwise (a) Use the Fourier series expansion formula (the Fourier sum) to plot the function f(t) over two periods, given that the period is T= 1 seconds. That means: use the Fourier series sum with the given coefficients and fundamental frequency. Cut off your Fourier expansion sum at some 'reasonable' number (n = 25 should work well for this problem) so that Maple can actually compute the finite sum. Plot the function (your cut-off Fourier series sum) for t=0..2 (2) since the given period is 1/2. (b) Repeat part (a) but now using a period of T=2 seconds (this means you use the same cut-off Fourier series sum, the same Fourier coefficients as part (a) but now your fundamental frequency is different). (c) What is the difference between part (a) and (b)