Suppose the following is a possible distribution of the number of crashes a driver will have...

     

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Suppose the following is a possible distribution of the number of crashes a driver will have over the course of their lifetime. X P(X = x) 0 0.01 1 2 (b) Find P(X< μ) or P(X> μ). P(x < μ)= P(x > μ)= 0.04 0.15 (a) Compute μ = E(X). HINT [See Example 3.] E(X) = 3 0.24 4 0.27 5 6 0.17 0.08 7 0.02 8 0.01 Interpret the result. This was the most frequently observed number of crashes for a driver. A driver will have at least this many crashes over the course of their lifetime. The average driver will have this many crashes over the course of their lifetime. O A driver will have at most this many crashes over the course of their lifetime. 9 0.01 Interpret the result. Then P(x>) is ---Select--- P(x <u). Thus, most drivers will have ---Select-- the average number of crashes. Suppose the following is a possible distribution of the number of crashes a driver will have over the course of their lifetime. X P(X = x) 0 0.01 1 2 (b) Find P(X< μ) or P(X> μ). P(x < μ)= P(x > μ)= 0.04 0.15 (a) Compute μ = E(X). HINT [See Example 3.] E(X) = 3 0.24 4 0.27 5 6 0.17 0.08 7 0.02 8 0.01 Interpret the result. This was the most frequently observed number of crashes for a driver. A driver will have at least this many crashes over the course of their lifetime. The average driver will have this many crashes over the course of their lifetime. O A driver will have at most this many crashes over the course of their lifetime. 9 0.01 Interpret the result. Then P(x>) is ---Select--- P(x <u). Thus, most drivers will have ---Select-- the average number of crashes.