Question: Suppose you run the following program on your shell. int i = 0; main() { } printf(%d , i); fork(); i = i +
Suppose you run the following program on your shell. int i = 0; main() { } printf("%d ", i); fork(); i = i + 2; printf("%d ", i); fork(); i = i + 3; printf("%d ", i); Please explain what you will see on your screen after you run this program/script and why.
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Answer Lets break down the provided code step by step int i 0 declares an integer variable i and ini... View full answer
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