Question: The angular position of a point on a rotating disk is given by = (-0.37) 3+ (-0.73) 2 + (-3.87) t+ (72), where e

The angular position of a point on a rotating disk is given

The angular position of a point on a rotating disk is given by = (-0.37) 3+ (-0.73) 2 + (-3.87) t+ (72), where e is in radians and t is in seconds. What is its angular acceleration in rad/s at t=21 sec? Round your answer to two decimal places.

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