The ANOVA summary table for an experiment with six groups, with five values in each group, is shown to the Degrees of Sum of Mean right. Complete parts (a) through (b below. Source Freedom Squares Square (Variance) F Among C - 1 =5 SSA = 750 MSA = 150 FSTAT = 5.00 groups Within n - c = 24 SSW = 720 MSW = 30 groups Total n - 1= 29 SST = 1470 . . . a. At the 0.05 level of significance, state the decision rule for testing the null hypothesis that all six groups have equal population means. Determine the hypotheses. Choose the correct answer below. O A. Ho: My = H2= . . . = 15 OB. Ho: My = 12= . . . = HG Hy: My $ H2 # . . . # 15 Hy: Not all the means are equal. O C. Ho: My = 12= . . . = 15 OD. HO: M1 = H2= . . . = H6 H: Not all the means are equal. Hy: My # Hz z . . . F HG Find the test statistic. FSTAT = (Round to two decimal places as needed.) Determine the critical value. Fa = (Round to two decimal places as needed.) b. What is your statistical decision? Ho. There is evidence to conclude that there is a difference in the population means of the groups