The average energy E $($in kcal$)$ needed for a lizard to walk or run a distance of $1$ km has been modeled by the equation

E$($m$,$ v$)=2\mathrm{.}65$m$0\mathrm{.}66+$

$3\mathrm{.}5$m$0\mathrm{.}75$v

where m is the body mass of the lizard $($in grams$)$ and v is its speed $($in km$/$h$).$ Calculate

Em$(380,9)$

and

Ev$(380,9)$

and interpret your answers.$$

Em$(380,9)=$ kcal$/$g

$($rounded to one decimal place$),$ so the rate at which the energy a lizard needs is changing as its weight increases is kilocalories per gram when

m $=$ g

and

v $=$ km$/$h$.$

Ev$(380,9)$ kcal$/($km$/$h$)$

$($rounded to one decimal place$),$ so the rate at which the energy a lizard needs is changing as its speed increase is kcal of energy for each $1$ km$/$hr increase in speed, when

m $=$ g

and

v $=$ km$/$h$.$