Question: The blackbody distribution function is given by 1(1.7) = 2rthc? * (chemat - 1) ce speed of light = 2.998 x 10^8 m/s h =

The blackbody distribution function is given by 1(1.7) = 2rthc? * (chemat - 1) ce speed of light = 2.998 x 10^8 m/s h = 6.62607015x10-34 3.5 Kb= 1.380649x10^-23J/k Use Mathematica to 1- Create exactly the same figure shown below. 5x 1013 T = 5000K 4x 1013 3x 1013 KA, T) (Watts/m) 2x 1013 T = 4000K 1x 1013 T = 3000K 0 5. x 10-7 1.x 10-6 1.5x 10-6 2.x 10-6 2.5x 10-6 1 (m) 2. Find the peak wavelengths corresponds to T = 3000, 4000 and 5000 K. I(1,7)= 27thc? (ehe/k27 1) c= speed of light = 2.998 x 10^8 m/s h = 6.62607015x10-34 Js Kb= 1.380649x10^-23 J/k The blackbody distribution function is given by 1(1.7) = 2rthc? * (chemat - 1) ce speed of light = 2.998 x 10^8 m/s h = 6.62607015x10-34 3.5 Kb= 1.380649x10^-23J/k Use Mathematica to 1- Create exactly the same figure shown below. 5x 1013 T = 5000K 4x 1013 3x 1013 KA, T) (Watts/m) 2x 1013 T = 4000K 1x 1013 T = 3000K 0 5. x 10-7 1.x 10-6 1.5x 10-6 2.x 10-6 2.5x 10-6 1 (m) 2. Find the peak wavelengths corresponds to T = 3000, 4000 and 5000 K. I(1,7)= 27thc? (ehe/k27 1) c= speed of light = 2.998 x 10^8 m/s h = 6.62607015x10-34 Js Kb= 1.380649x10^-23 J/k

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