The code below is an example shown in class last week.

What happens when the 'break' command is executed $($that is$,$ if $($r$+$c$)==0$ is true$)?$

n$=10$;

a$=$zeros$($n$+1,$n$+1)$;

for r $=0$:n

for c $=0$:n

if $(($r$+$c$)==0)$

break;

end

a$($r$+1,$c$+1)=1/($r$+$c$)$;

end

if $($r$==0)$

continue;

end

a$($r$+4,$r$+4)=10$;

end

Group of answer choices

Both the loop on c and the loop on r are stopped and the code finishes.

The command a$($r$+1,$c$+1)=1/($r$+$c$)$; gets executed with r$=0$ and c$=0$

The entire loop on c is stopped, and the next iteration of the for loop on r starts with r$=1.$

Nothing happens at all