Question: The code shown below is compiled and executed, does the thread that is created have access to the variable flag? a. Yes, because all the
The code shown below is compiled and executed, does the thread that is created have access to the variable "flag"?

a. Yes, because all the threads in the same process share the data segment of the process.
b. Yes, because all the threads in the same process share the heap of the process.
c. No, because threads do not share the heap of the process.
d. No, because threads do not share the data segment of the process.
typedef struct { int arg1; char arg2; } args_t; int flag; void *thread_func (void *arg) { args_t *args = (args_t *) arg; /* some lines of code here not shown */ return NULL; } int main() { pthread_t thr; args_t args = {100, 'z'}; char *chars = malloc (1024*sizeof(char)); int nums [1024]; for (int i=0; i
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
