The equation of tangent line of the function 7x f(x) = at x=1 is 7x 2...
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The equation of tangent line of the function √7x³ f(x) = at x=1 is 7x 2² dt Oy = ²√7 e¹4 (x-1) Oy = 2√7 0⁹8 (x-1) Oy = 2/2 √7 e²8 (x-1) Oy = √7 e¹4 (x-1) Oy = √7e⁹8 (x-1) The equation of tangent line of the function √7x³ f(x) = at x=1 is 7x 2² dt Oy = ²√7 e¹4 (x-1) Oy = 2√7 0⁹8 (x-1) Oy = 2/2 √7 e²8 (x-1) Oy = √7 e¹4 (x-1) Oy = √7e⁹8 (x-1)
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Lets solve this stepbystep We are given the function fx 7x7x3 e2t2 dt To find the tangent line at ... View the full answer
Related Book For
Income Tax Fundamentals 2013
ISBN: 9781285586618
31st Edition
Authors: Gerald E. Whittenburg, Martha Altus Buller, Steven L Gill
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