Question: The figure below shows a 16-bit carry-bypass adder. The inputs are denoted as (A 15 A 14 A 0 ) and (B 15 B 14

The figure below shows a 16-bit carry-bypass adder. The inputs are denoted as (A15A14…A0) and (B15B14…B0), where A15 and B15 are the MSBs. Pi and Gi follow the definitions in the lecture (i.e., Pi=Ai xor Bi, Gi=Ai & Bi). Outputs Si are omitted for simplicity. Please note that independent calculations can be performed concurrently in hardware (e.g., all Pi’s and Gi’s can be calculated simultaneously).


BP= P PP:P, AB A,B A,B A,B FA FA FA Co2 BP= PPP&P, AB AB AB A, B FARFA FA FA Cot Cos C06 BP=P&P,P10P11 AB

The following figure shows the detail inside each full adder based on P and G.




Ai Bi Ci Pi D D Si Ci + 1


Assume the following delay for each component: Producing P, G; from A., B (The left-hand-side circle): 1 unit 

BP= P.PP:P, AB A,B A,B A, B FA FA FA Co2 BP= PPP&P, AB AB AB A, B FARFA FA FA Cos C06 Cot BP= P&P,P10P11 AB A,B, A1B10 ALB11 FARFARFARFA Co Co.10 BP= P1:P13P14 P15 AB12 A1B13 AB4 A15B15 Coll FARFARFARFA Coll Co,13 Coll 0,15

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Inputs The adder takes two 16bit binary numbers A and B as inputs Each bit is labeled from A15 most significant bit to A0 least significant bit for A ... View full answer

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