The following circuit (i) shows the two parallel branches with inductive and capacitive loads. The circuit...

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The following circuit (i) shows the two parallel branches with inductive and capacitive loads. The circuit supply AC voltage is given by v(1). Derive general equation for overall (5 Marks) admittance of the circuit (1). The circuit (ii) has supply voltage of sin(1). Find the value of capacitance C when the power factor of the circuit is 0.8 lagging for the circuit (ii) using the derived results of (5 Marks) circuit (1). 100 www. www sin(1) I 10) wwwm 9 = The following circuit (i) shows the two parallel branches with inductive and capacitive loads. The circuit supply AC voltage is given by v(1). Derive general equation for overall (5 Marks) admittance of the circuit (1). The circuit (ii) has supply voltage of sin(1). Find the value of capacitance C when the power factor of the circuit is 0.8 lagging for the circuit (ii) using the derived results of (5 Marks) circuit (1). 100 www. www sin(1) I 10) wwwm 9 =

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Circuit i Deriving the General Equation for Overall Admittance The given circuit consists of two par... View the full answer