The following LC-3 instructions execute starting from the point shown by the comment.

0000 0000 0000 0110 ; this is the content of address D

0000 0000 0000 0011 ; this is the content of address D + 1

; start LC-3 execution here

0010 101 111111110

0010 110 111111100

0101 111 111 1 00000

0001 111 111 0 00 101

0001 110 110 1 11111

0000 001 111111101

1110 100 111110111

0111 111 100 000001

; end LC-3 execution here

After the code reaches the end of the code (the last comment), what bits are held in R4? And in R5? And in R6? And in R7? And in memory address D? And in memory address D + 1? If you cannot know the bits held, explain why.