It shows a CDMA example that supports two senders. Suppose that the receiver wanted to receive the data being sent by sender 2. Show (by calculation) that the receiver is indeed able to recover sender 2’s data from the aggregate channel signal by using sender 2’s code.

 

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senders data d = 1 bits di=-1 Sender 1 channel,Zi,m 110 1 111 code data df = 1 di = 1 Sender 2 bits code Zi,m Cm m=1 M = 1 d = -1 slot 1 received input slot 0 received input receiver 1 code 111 D 111 O senders data d = 1 bits di=-1 Sender 1 channel,Zi,m 110 1 111 code data df = 1 di = 1 Sender 2 bits code Zi,m Cm m=1 M = 1 d = -1 slot 1 received input slot 0 received input receiver 1 code 111 D 111 O