The following question will be graded

automatically.

The equation below will be used to

determine the vapor pressure of isopropanol

in this experiment:

$lnP=-(\frac{H_{\text{v}\text{a}\text{p}}}{RT})+C$

Let's assume that you run the experiment at

$21\mathrm{.}1C,27\mathrm{.}2C,33\mathrm{.}9C$ and $13\mathrm{.}1C$ with

the measured vapor pressure $56\mathrm{.}4mmHg,$

$80\mathrm{.}0mmHg,95\mathrm{.}1mmHg,$ and $48\mathrm{.}1mmHg,$

respectively. What is the $lnP$ for the

temperature at $27\mathrm{.}2($keep $5$SIGs $)$