1. The four span slab shown in Figure 1 supports a live load of 3.0 kN/m², plus floor finishes and ceiling load of 1.5 kN/m².
2. 

1. Determine:
2. The overall and effective depths of the slab, hence the ultimate load per metre width of the slab. Take basic span-effective depth ratio = 26, and initial tensile modification factor = 1.3. Assume the slab is exposed to mild conditions.
3. The area of main reinforcement, subsequently the size and centre-to-centre spacing of the bars required for:-
4. Mid-span of span AB. Check if the value of the effective depth obtained in (I) above is adequate. Assume end support is simply supported.
5. Mid-span of span BC.
6. The area of distribution steel, consequently the size and centre-to-centre spacing of the bars required.

1. Check the slab for the following failures, then take appropriate measures, if any, given that the ultimate shear stress is the lesser of 0.8Öf_cu or 5 N/mm², and the ultimate bond stress = 2.8 N/mm². Assume no curtailment of bars is done.
2. Shear

Local bond.

Transcribed Image Text:

7 m Beam Plan Span 5.2m Elevation Beam Span 5.2m Beam Span 5.2m Beam Span 5.2m Beam E 7 m Beam Plan Span 5.2m Elevation Beam Span 5.2m Beam Span 5.2m Beam Span 5.2m Beam E

Answer rating: 100% (QA)

Answer 1 a i Effective span 12 m Revised Ld ratio 20 x 1012 167 hence d 12000167 719 mm take d 720 h 720 50 770 mm Since 033 bh 05 b 05h 385 mm take b ... View the full answer