Question: The instantaneous angular position of a point on a rotating wheel is given by the equation 0(t) = 2t - 6t. The torque on

The instantaneous angular position of a point on a rotating wheel is

The instantaneous angular position of a point on a rotating wheel is given by the equation 0(t) = 2t - 6t. The torque on the wheel becomes zero at (a) t = ls (b) t = 0.5 s (c) t = 0.25 s (d) t = 2s

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