The internal shear force $V$ at a certain section of an aluminum beam is $6\mathrm{.}5$ kN $.$ If the beam has the cross section shown $($assume $a=34mm,b_f=62mm,t_w=t_f=7mm,d=66mm),$ determine:

$($a$)$ the shear stress ${}_H$ at point $H,$ which is located $34$ mm above the bottom surface of the tee shape.

$($b$)$ the maximum horizontal shear stress ${}_{\text{m}\text{a}\text{x}}$ in the tee shape.

Answers:

$($a$){}_H=$ MPa.

$($b$){}_{\text{m}\text{a}\text{x}}=$ MPa $.$

The internal shear force $V$ at a certain section of an aluminum beam is $6\mathrm{.}5$ kN $.$ If the beam has the cross section shown $($assume $a=34mm,b_f=62mm,t_w=t_f=7mm,d=66mm),$ determine:

$($a$)$ the shear stress ${}_H$ at point $H,$ which is located $34$ mm above the bottom surface of the tee shape.

$($b$)$ the maximum horizontal shear stress ${}_{\text{m}\text{a}\text{x}}$ in the tee shape.

Answers:

$($a$){}_H=$ MPa.

$($b$){}_{\text{m}\text{a}\text{x}}=$ MPa $.$