The internal shear force $V$ at a certain section of an aluminum beam is $10\mathrm{.}6kN.$ If the beam has the cross section shown $($assume $a=36$

$mm,b_f=76mm,t_w=t_f=7mm,d=75mm),$ determine:

$($a$)$ the shear stress ${}_H$ at point $H,$ which is located $36mm$ above the bottom surface of the tee shape.

$($b$)$ the maximum horizontal shear stress ${}_{\text{m}\text{a}\text{x}}$ in the tee shape.

Answers:

$($a$){}_H=$

MPa.

$($b$){}_{\text{m}\text{a}\text{x}}=$