Question: The Maclaurin senes for the function 1/x is given as 1/x=1(x1)+(x1)2(x1)n3+(x1)n4 The true percent relative error in the value of the estimate of the function

 The Maclaurin senes for the function 1/x is given as 1/x=1(x1)+(x1)2(x1)n3+(x1)n4

The Maclaurin senes for the function 1/x is given as 1/x=1(x1)+(x1)2(x1)n3+(x1)n4 The true percent relative error in the value of the estimate of the function at x=0.4 using only the first 3 terms of the senes is Give answer to 1 decimal place and don't include the % sign

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