Question: the MAD for method 2 = ? Following are too weekly forecasts made by two different methods for the number of gallons of gasoline, in

the MAD for method 2 = ? the MAD for method 2 = ? Following are too weekly
the MAD for method 2 = ? Following are too weekly
Following are too weekly forecasts made by two different methods for the number of gallons of gasoline, in thousands, demanded at a local station. Also shown are actual demand levels in thousands of a Week Week 1 2 3 4 Forecast Method: 0.90 1.05 0.97 1.20 Actual Demand 0.70 0.90 100 1.00 Forecast Method 2 0.77 121 0.00 1 17 2 3 4 Actual Demand 0.70 00 100 100 The MAD for Method - 0.125 thousand galios found your response to the decimal The mean suared error (ME) for Method 10.021 thousand alone found your own to the places The MAD for Metrid 2 - thousand gain for your response to tima po Following are two weekly forecasts made by two different methods for the number of gallons of gasoline, in thousands, demanded at a loca Week Week 1 2 3 4 Forecast Method 1 0.90 1.05 0.97 1.20 Actual Demand 0.70 0.98 1.00 1.00 1 2 3 4 Forecast Method 2 0.77 1.21 0.90 1.17 Actual Demand 0.70 0.98 1.00 1.00 The MAD for Method 1 = 0.125 thousand gallons (round your response to throw decimal places). The mean squared error (MSE) for Method 1.0.021 thousand gallons? (round your response to three decimal places). The MAD for Method 2 -thousand gallons (round your response to three decimal places)

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