The molecular weight and formula of a hydrocarbon are to be determined through the use of the freezing point depression method. The hydrocarbon is known to be 86% carbon and 14% hydrogen by mass. In the experiment, 3.72 grams of the unknown hydrocarbon were placed into 50.0 grams of liquid benzene, C6H6. The freezing point of the solution was measured to be 0.06oC. The normal freezing point of benzene is 5.50oC and the freezing point depression constant for benzene is 5.12 oC/m.

1. What is the empirical formula for the hydrocarbon? Calculate the molar mass for this empirical formula.
2. Calculate the freezing point depression.
3. Calculate the moles of hydrocarbon added to the benzene.
4. Calculate the molar mass (g/mole) of the hydrocarbon.
5. What is the molecular formula for the hydrocarbon?

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a 860 g C 1C 1201gc 716 m C 716 1 140 g H 1mH101g 13... View the full answer