The PA trip table in a four$-$zone network is given below:

$\backslash$table$[[$FromTAZ$\backslash$ToTAZ$,1,2,3,4],[1,0,150,200,0],[,,,,50],[2,0,0,400,0],[3,0,0,0,0],[4,0,0,0,0]]$

The utility functions for auto and transit modes are defined as follows:

Auto Utility Equation: $U_A=-0\mathrm{.}028($IVT$)-0\mathrm{.}055(OVT)-0\mathrm{.}0022($COST$)$

Transit Utility Equation: $U_B=-0\mathrm{.}028($IVT$)-0\mathrm{.}055($OVT$)-0\mathrm{.}10($WAIT$)-0\mathrm{.}20($XFER$)0\mathrm{.}0022($COST$)$

Note: IVT$=$In$-$Vehicle Travel Time, OVT$=$Out$-$of$-$Vehicle Travel Time, XFER$=$Transfer Time The data for each PA pair are:

$\backslash$table$[[,1,2,3,4],[1,,\backslash$table$[[$Auto: IVT$=20],[$OVT$=4,$COST$=$$$1]],\backslash$table$[[$Auto: IVT$=42,],[$OVT$=5,$COST$=$$$2]],],[,\backslash$table$[[$Transit: IVT$=30,$ OVT$=8,],[$WAIT$=10,$ XFER$=0,],[$COST$=$$$0\mathrm{.}5]],\backslash$table$[[$Transit: IVT$=60,$ OVT$=15,],[$WAIT$=25,$ XFER$=2,$ COST$=$$$2\mathrm{.}5]],],[2,,,\backslash$table$[[$Auto: IVT$=34,],[$OVT$=4,$COST$=$$$1\mathrm{.}5]],\backslash$table$[[$Auto: IVT$=30],[$OVT$=3,$COST$=$$$1\mathrm{.}25]]],[,,\backslash$table$[[$Transit: IVT$=48,$ OVT$=12,],[$WAIT$=20,$ XFER$=1,$ COST$=$$$1\mathrm{.}5]],\backslash$table$[[$Transit: IVT$=42,$ OVT$=8,],[$WAIT$=15,$ XFER$=1,$ COST$=$$$1\mathrm{.}25]]],[3],[4,,,,]]$

Calculate the person trips for each mode and each PA pair.

Auto Person Trip Table

$\backslash$table$[[,1,2,3,4],[1,,,,],[2,,,,],[3,,,,],[4,,,,]]$

Transit Person Trip Table

$\backslash$table$[[,1,2,3,4],[1,,,,],[2,,,,],[3,,,,],[4,,,,]]$